Subnetting examples with answers
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All its host bits are zero. A Subnet mask can be written in two ways; in full form and in abbreviated form. To further this analogy, think of a router as a post office. Subnetting can be done only in Subnetting eligible bits. On a second line, write down the broadcast mask. If I tried to extend it by 3 bits only, the maximum subnets allowed would be only 8 subnets rule 2 in. But it's been a little while, and I don't know everything of course.

The broadcast mask is formed by using 0s for the subnet bits and 1s for the host bits. This is one of the many methods available. If you still do not remember the weights of all bits, you may consider using this little aid presented below pic. What is the subnet mask for the maximum number of hosts? The router is using the first valid host address in the range. In other words, 32 bits equals 32 zeroes or ones. Convert the shorthand subnet mask to decimal.

Your organization requires 900 subnets, with at least 50 hosts per subnet. If these questions seem too difficult, start out with our questions. Answer 2In order to determine the subnet and broadcast address of the subnet of this host address, we must look at the length of the network mask first. In this example, the first two octets are identical, so we know the first 16 bits are common across all four networks. In this example, it is the first network. What subnet mask should you use? Answer B is incorrect because it is your original subnet mask.

Multiple choice and true or false type questions are also provided. Both addresses are always used together. Given Address Value after slash Interesting octet Upper value of range Subtraction 10. This tutorial is the second part of the article. Both addresses are 32 bits in length. Step 3: Count the number of common bits in the mask. Answers B, C, and D are incorrect because auto-summarization only summarizes back to a classful boundary rather than to more specific subnet masks.

Each part is known as octet and contains 8 bits. To best utilize available addresses if we put more than 16000000 hosts in a single network, due to broadcast and collision, that network will never work. This tutorial is the sixth part of the article. Decimal Number 3 0 1 1 ---- ---- ---- 4 2 1 Now we simply add each decimal number on the bottom each time we see a binary 1. This is not a valid host address in this network. Answer D uses the underscore character, which is invalid.

In other words, you would get 100% on 40% of the exam. For example if we want to know many networks can be created from 3 Subnetting bits, we will use power 2 three times. In this case, the FastEthernet interface has the subnet mask 255. Block Size Block size is the sum of network address, valid host addresses and broadcast address. A subnet mask of 255. In addition, the first six bits of the third octet are also common.

All other combinations result in False, such as when both bits are True or both bits are False. Which subnet mask would you choose? This will give us the number of the host bits remaining in host portion. The router's interface is in the 2. X Step 3 Just like we did above, based on interesting octet, subtract the given value from the upper value of interesting octet range. Subnetting can only be done in host portion.

But in exam and interview, where time and accuracy matter, you should always use the easiest and the fastest methods of Subnetting such as explained in this tutorial. Computer networks are similarly malleable. These bits are divided in four parts. Subnetting provides a better way to deal with this situation. Other parts of this article are following. For example value in interesting octet is 27 and block size is 8 then the range will be 24-31 0-7, 8-15, 16-23, 24-31. Answers B and D are incorrect because they use the incorrect command.

Final possible masks are: 255. All other answers produce an invalid syntax or incomplete command message. Note that the sum of the network subnet mask and the network broadcast mask is always 11111111 11111111 11111111 11111111 in binary, or 255. Genuinely curious, not questioning your abilities. Since three bits went to the subnet in step 2, we have five host bits 0's remaining. Subtract the given network bits from the reserved network bits.